Thread: This pointers a mystery, please help with my misery.

Hey Guys,

This is a crazy problem. I'm doing some testing to make sure I understand how to use the pointers to arrays before I finish the code. If I run the code and type in 00 or 11 it works correctly or at least appears to. If you type in 10, the result is 'twenty'. It's crazy!

Code:

//http://knking.com/books/c2/answers/c13.html
#include <stdio.h>


int main(){
    char *digOne[]={"twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninety"};
    char *digTwo[]={"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    char *digThree[]={"ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
    char num[2];
    printf("Enter a two-digit number: ");
    scanf("%s", num);


    if(num[0]==48&&num[1]==48){         //if 00 is entered
        printf("%s",digTwo[0]);         //prints zero
    }
    else if(num[0]==49&&num[1]==48){    //if 10 is entered
        printf("%s",digThree[0]);       //prints twenty?   CRAZY!!!
    }
    else if(num[0]==49&&num[1]==49){    //if 11 is entered
        printf("%s",digThree[1]);       //prints eleven
    }
    return 0;
}

If I comment out

Code:

//char *digOne[]={ ...

and then run the program, if I enter 10 again, it prints zero. What The Heck is wrong with what I wrote or with my head?

Here's a screen capture.

Do you realize that you are overflowing the bounds of the "num" array when you enter more than one character?

Remember that the "%s" specifier retrieves a string, automatically adding the end of string character to the end of the string.

You need an array of at least size 3 and you should specify the number of characters scanf() should try to retrieve to avoid buffer overflow.

OMG guys. Thank you very much. So many of my bugs are stupid errors. Embarrassed. For what it's worth, I'm off of my project and reading a book as suggested by this forum...