Loading numbers into array problem

[grepawk]

Hello i am trying to make code which will request user for his phone number (on one line), that number will be stored in array number, everything works ok till i dont type less then 10 numbers and press enter, cycle is waiting for next number/s on new line but i want program to give message like: number is too short or too long , type that number again: i have tried many options with while cycle and do while but none of them works properly

#define ARRAYSIZE(a)   (sizeof(a) / sizeof(a[0]))
int main()
{
  int number[10];
   printf("type your number: \n");
   for (int i = 0; i < ARRAYSIZE(number); i++)
   {
    scanf("%1d",&number[i]); //fe input: 033232313 is correct 
            //123 is incorrect user will be able to type numbers again 
   }
  ...
}

Thanks in advance for any help...

[john.c]

You probably need to read the input line into a string first and then extract the digits from the string.

[Salem]

You can't really store phone numbers in integers.

To begin with, integers do not store leading zeros.

This is a big problem when you have international numbers like 004212345678

Then some (actually a lot) of numbers have more digits than can be stored in a 32-bit integer.
Phone Number Length by Country 2022 - World Populace

To reliably deal with phone numbers, read them in as a string.