Thread: How to make the function being able to to continue a while loop while being outside

I already learned that continue or break works only while being inside the loop.
My question is that is there any way to outsmart this or is there any way besides continue to make it work...

In the code I'm talking about the function q_what_to_do_next, how to make this outside function do the continue work?

Code:

#define _CRT_SECURE_NO_WARNINGS


#include <stdio.h>
#include <stdlib.h>
#include <windows.h>
#include <limits.h>
#include <string.h>
#include <math.h>


int q_what_to_do_next();


int main()
{
    int a = INT_MAX;
    while (1)
    {
        if (a != INT_MAX)
        {
            //nuline programa, jei nori baigti programa
            if (a == 0)
            {
                system("cls");
                char p;
                printf("Ar tikrai norite iseiti is programos?\n");
                printf("Jei taip, spauskite y\n");
                printf("Jei ne, spauskite n\n");
                scanf(" %c", &p);
                if(p != 'y' && p!='n')
                {
                    system("cls");
                    int i;
                    printf("Kadangi pasirinkote ne y arba n busite automatiskai ismestas is programos uz 10 sekundziu\n");
                    Sleep(5000);
                    for (i = 1; i <= 10; i++)
                    {
                        printf("%d\n", i);
                        Sleep(1000);
                    }
                    break;
                }
                if (p == 'y')
                    break;
                else if(p =='n')
                {
                    a = INT_MAX;
                    system("cls");
                    continue;
                }


            }
            //pirmoji programa
            else if (a == 1)
            {
                system("cls");
                int binary;
                int bp = 0; //bp - isaugojimas pradiniu duomenu
                int decimal = 0;
                int k = 0; //pagalbinis skaiciuojant desimtaini
                int m = 1; //kitas pagalbinis, kuris dides
                printf("***********************************************************************************\n");
                printf("**  Iveskite savo norima dvejetaini koda, kuri noretumete paversti desimtainiu:  **\n");
                printf("***********************************************************************************\n");


                while (scanf(" %9d", &binary) != 1 || getchar() != '\n')
                {
                    printf("Iveskite dvejetaini skaiciu!\n");
                    while (getchar() != '\n')
                        ;
                }


                bp = binary;


                while (bp > 0)
                {
                    k = bp % 10;
                    decimal = decimal + k * m;
                    bp = bp / 10;
                    m = m * 2;
                }
                system("cls");
                //pagrindas 40 H raidziu
                double sk = 0, sk1 = 0;
                sk = (decimal == 0) ? 1 : log10(decimal) + 1;
                sk1 = (bp == 0) ? 1 : log10(bp) + 1;
                double n = sk + 5;
                printf("HHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH");
                while (n > 0)
                {
                    printf("H");
                    n--;
                }
                printf("\n");


                printf("HH  Jusu pasirinktas dvejetainis kodas: %d", binary);




                n = sk + 5;
                while (n > 0)
                {
                    printf(" ");
                    n--;
                }
                printf("HH\n");


                n = sk + 5;
                printf("HHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH");
                while (n > 0)
                {
                    printf("H");
                    n--;
                }
                printf("\n");




                printf("HH  Gautas desimtainis kodas, konvertutoas is dvejetainio: %d", decimal);
                printf("  HH\n");




                n = sk + 5;
                printf("HHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH");
                while (n > 0)
                {
                    printf("H");
                    n--;
                }
                printf("\n");


                a = q_what_to_do_next();
            }
            else
                {
                system("cls");
                int b = 0;
                printf("Nera tokios programos\n");
                printf("Paspauskite 1, kad galetumete is naujo pasirinkti\n");
                while (scanf(" %d", &b) != 1 || getchar() != '\n' && b!=1)
                {
                    printf("NU siupele tu siupele!\n");
                    printf("VIENETAAA, ne kazka kito\n");
                    while (getchar() != '\n')
                    ;
                }
                if (b == 1)
                {
                    system("cls");
                    a = INT_MAX;
                    continue;
                }
            }
        }
        else
        {
            printf("\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\n");
            printf("|         Programos veiksmu pasirinkimas:         |\n");
            printf("|irasykite skaiciu, kurios programos dalies norite|\n");
            printf("///////////////////////////////////////////////////\n");
            printf("|1 - is dvejetaines i desimtaine                  |\n");
            printf("|2 - is dvejetaines i sesioliktaine               |\n");
            printf("|3 - is desimtaines i dvejetaine                  |\n");
            printf("|4 - is desimtaines i sesioliktaine               |\n");
            printf("|5 - is sesioliktaines i dvejetaine               |\n");
            printf("|6 - is desioliktaines i desimtaine               |\n");
            printf("|0 - iseiti is programos                          |\n");
            printf("\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\n");
            while (scanf(" %d", &a) != 1 || getchar() != '\n')
            {
                printf("LOPETA TU!\n");
                printf("TIK VIENA SKAICIU, BE JOKIO TARPO, BE RAIDZIU!\n");
                printf("Nebuk kaip Grazulis ble...\n");
                while (getchar() != '\n')
                    ;
            }
            continue;
        }
        
        system("cls"); //clear screen
    }
    exit(0);
    return 0;
}


int q_what_to_do_next()
{
    int p;
    printf("Jie norite pakartoti programa spauskite 1\n");
    printf("Jei norite grizti i programu pasirinkimo langa spauskite 2\n");
    printf("Jei norite baigti programa spauskite 3\n");
    while (scanf(" %d", &p) != 1 || getchar() != '\n')
    {
        printf("Iveskite skaiciu is pasirinkimu, ne kazka kito\n");
        while (getchar() != '\n')
            ;
    }
    if (p == 1)
    {
        //a = 1;
        return 1;
        continue;
    }
    if (p == 2)
    {
        system("cls");
        //a = INT_MAX;
        return INT_MAX;
        continue;
    }
    else
    {
        system("cls");
        //a = 0;
        return 0;
        continue;
    }
}

while (1) is an infinite loop, breaking out of it is considered as side-effect.

Thank you

I think I get what you are asking...

"continue" can not reach outside of a function. To do what you want, the function has to signal back to the caller that it should continue:

Code:

int my_founction(int x, int y, int z) {
     if( x == y)
         return 0;   // Failure
     return 1;  // Success
}

...

void main_loop(void) {
    while(1) {
        // Set x,y,z to values
        if(my_function(x,y,z)) {
            continue;
        }
    }
}

The only other way is to use things like "setjump()" and "longjump()" -but that is not the solution you should be using.

Thanks, thats what I needed, you are right on the spot