Thread: Is there any possible way to convert this program from C++ to C?

insert

Code:

#include <bits/stdc++.h>
using namespace std;
 
// Function to string into grid form
void gridStr(string str)
{
    int l = str.length();
    int k = 0, row, column;
    row = floor(sqrt(l));
    column = ceil(sqrt(l));
 
    if (row * column < l)
        row = column;
 
    char s[row][column];
    // convert the string into grid
    for (int i = 0; i < row; i++) {
        for (int j = 0; j < column; j++) {
            s[i][j] = str[k];
            k++;
        }
    }
 
    // Printing the grid
    for (int i = 0; i < row; i++) {
        for (int j = 0; j < column; j++) {
            if (s[i][j] == '\0')
                break;
            cout << s[i][j];
        }
        cout << endl;
    }
}
 
// Driver code
int main()
{
    string str = "GEEKSFORGEEKS";
    gridStr(str);
     
    return 0;
}

The code is actually very C-like.

You only need to replace the usage of the C++ standard library with corresponding C API, do the same for the header files and use 'char *' in place of 'string str'. Well, that looks like pretty much it.

So basically it asks for a key and string. The length of the key determines how many columns in the matrix there are. However I call the strlen function but it doesn't work. It keeps on giving me the length of the string as 6.

insert

Code:

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include <math.h>


int main(){
	char str[50];
	char key[50];
	
	printf("Please enter string:");
	gets(str);
	
	printf("Please enter key:");
	gets(key);
	
    gridStr(str);
    
    return 0;
}
void gridStr(char *str, char *key)
{	


	int columns = (strlen(key));
    int i = 0;
    while (str[i]) {
        putchar(str[i++]);
        if (i % columns == 0) putchar('\n');
    }
    if (i % columns != 0) putchar('\n');
}