I am getting really confused now, if i have a signed value for example -634, what will the MSB and LSB of the number?
I am getting really confused now, if i have a signed value for example -634, what will the MSB and LSB of the number?
Assuming two's complement representation, -634 in 16 bits has the same bit pattern as 2**16 - 634 = 65536 - 634 = 64902 which in hex is 0xFD86. So the MSB is 0xFD and the LSB is 0x86. However, the order that the MSB and LSB are stored in memory depends on the endianness of your system. If it is little-endian then 0x86 will appear first (lower in memory) and 0xFD will appear after that.
The whole problem with the world is that fools and fanatics are always so certain of themselves, but wiser people so full of doubts. - Bertrand Russell
Intel/AMD architecture are Little-Endian by default. There are compiler options in most compilers to change that.Originally Posted by Clearner123
See the Wikipedia article for more information.
It's apparently useless trying to help this person.
The whole problem with the world is that fools and fanatics are always so certain of themselves, but wiser people so full of doubts. - Bertrand Russell
Why do you think so, any reason?
It is sometime very hard to tell the difference between a newbie and a "help vampire"!
You are looking more like an "help vampire" than is considered good.
Tim S.
"...a computer is a stupid machine with the ability to do incredibly smart things, while computer programmers are smart people with the ability to do incredibly stupid things. They are,in short, a perfect match.." Bill Bryson
He's also asking the same or similar questions in multiple threads.
And his initial thread says he is writing the code for a "customer".
That customer is being ripped off since obviously doesn't know what he's doing.
And how do we get our cut of the profits?
The whole problem with the world is that fools and fanatics are always so certain of themselves, but wiser people so full of doubts. - Bertrand Russell
