Thread: variable used but uninitialized

  1. #1
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    variable used but uninitialized

    Hy everyone, I need your help !
    I'm doing a little code for school but I have an issue : when I try to compile my code I have the following warning : "warning: 'nom' is used uninitialized [-Wuninitialized]".
    My issue is that nom is initialized two line above. Is someone could help me ?

    Code:
    char *demande_nom1()
    {
      char *nom;
      printf("Quel est le nom de l'image d'origine ?");
      scanf("%s", nom);
      return nom;
    }
    PS: yes i'm french
    Last edited by Salem; 04-15-2022 at 11:29 AM. Reason: Removed crayola

  2. #2
    and the hat of int overfl Salem's Avatar
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    Initialised means you used the = operator to give your variable a value.

    Hence uninitialised means you didn't do that, and you've no idea where nom is pointing.

    To make this code workable, you need something like
    char *nom = malloc(100);
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

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