Thread: Why program print two different locations

In program I am expecting address of 'new' and address of first member sould be same

Code:

#include<stdio.h>

#include<stdlib.h>


struct node 
{
    int data;
    struct node *next;
};


struct node *Add( struct node * Head, int value)
{
    struct node * new = malloc(sizeof(*new));
    printf("addresses of a new : %p \n", (void*)&new);    
    
    if( new != NULL )
    {
        new -> data = value;
        printf("addresses of first member : %p \n", (void*)&new->data);
        new -> next = NULL;
    }


 return new; 
}    


int main ()
{
    struct node * head = NULL ;    
    head = Add( head, 1);
    return 0;
}

When I run code I don't understand why I get difffferent value

addresses of a new : 0061FEEC
addresses of first member : 00C10D18

Originally Posted by Salem

> printf("addresses of a new : %p \n", (void*)&new);
You're printing the address of your local variable.

Not the result of the malloc call.

Use
printf("addresses of a new : %p \n", (void*)new);

'new' is local variable that hold memory location but what's memory address of new where it is stored. Is 0061FEEC address of new where it hold memory location of other variable