Hi all, I'm having a little bit of trouble with my code about structures
I have decleared structure and I want to initialize array in single statement
errorCode:#include<stdio.h> #include<stdlib.h> struct point { int array[5]; }; int main() { struct point svar; struct point spvar; svar.array[5] = {1, 2, 3, 4, 5}; return 0; }
Code:error: expected expression before '{' token svar.array[5] = {1, 2, 3, 4, 5}
can anyone tell me what's the reason of error
You are setting the sixth element to a array.
TryCode:svar.array[5] = {1, 2, 3, 4, 5};
My Bad.. Try thisCode:svar.array = {1, 2, 3, 4, 5};
Code:#include <stdio.h> #include <stdlib.h> struct point { int array[5]; }; int main(int argc, char ** argv) { struct point svar = {{1,2,3,4,5}}; struct point spvar; return 0; }
Last edited by G4143; 03-01-2022 at 10:02 PM.
I tried that but I am getting same error. I have GCC compilerOriginally Posted by G4143
Unfortunately, you cannot assign to an array itself. However, you can initialise them, and in this case it means initialising the struct of which the array is a member:
or if you want to consider that the struct may have more members:Code:struct point svar = {1, 2, 3, 4, 5};
Code:struct point svar = {{1, 2, 3, 4, 5}};
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when code run it gives output 1 6422296 4199048 0 4199157 and I was expecting 1, 2, 3, 4, 5Code:#include<stdio.h> #include<stdlib.h> struct point { int array[5]; }; int main() { int i; struct point *spvar; struct point svar = {{1, 2, 3, 4, 5}}; spvar = &svar; for ( i = 0; i < 5; i++) { printf( "%d ", *spvar ); spvar++; } return 0; }
You have to understand C and pointers..
This pointer is not pointing at an integer, its pointing at a struct. Just for your benefit. Try taking the sizeof(int) and the sizeof(struct point).Code:struct point *spvar;
spvar is a pointer to struct point. Therefore, *spvar is a struct point. So what you're doing here:
is trying to print a struct point object as if it were an integer. It isn't. Your compiler should have warned you about that, and if it didn't, you need to compile at a high warning level and pay attention to warnings.Code:printf( "%d ", *spvar );
What you want to do is something like this:
Code:#include<stdio.h> #include<stdlib.h> struct point { int array[5]; }; int main(void) { struct point svar = {{1, 2, 3, 4, 5}}; for (size_t i = 0; i < 5; i++) { printf("%d ", svar.array[i]); } printf("\n"); return 0; }
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