Thread: dynamic array

In my code, I am allocating memory for 2 elements first, then assigning value at each memory location. when I print them I get their values.

then I allocate memoary for more 3 elements then assigning value at each memory location. when I print them I get their values.

Now I have total five elements which are stoared at five memory location.

I want to print all the five elements but when i print their value I don't get expected value

Code:

#include <stdio.h>

 #include <stdlib.h> 
  
int main() 
{     
    int i;
  
    // Dynamically allocate memory using malloc() 
      int* ptr = (int*)malloc(2 * sizeof(int)); 
  
    // Check if the memory has been successfully 
    // allocated by malloc or not 
    if (ptr != NULL) 
    { 
        // Memory has been successfully allocated 
        printf("Memory successfully allocated using malloc.\n"); 
  
    // Get the elements of the array 
       for (i = 0; i < 2; i++) 
       { 
           printf("The elements of the array are: ");
           scanf ("%d", ptr + i);            
        } 
  
        // Print the elements of the array 
        printf("The elements of the array are: "); 
        for (i = 0; i < 2; i++) 
        { 
            printf("%d, ", *(ptr  + i)); 
        } 
    } 
 
 
        
    // Dynamically allocate memory using malloc() 
      ptr = (int*)realloc(ptr, 3 * sizeof(int)); 
  
    // Check if the memory has been successfully 
    // allocated by malloc or not 
    if (ptr != NULL)
        { 
          printf("\n Enter the 3 more the elements of the array are \n");
    
           // Get the elements of the array 
           for (i = 0; i < 3; i++) 
            { 
                printf("The elements of the array are: ");
                scanf ("%d", ptr + i);            
            } 
  
            // Print the elements of the array 
            printf("\nThe elements of the array are: "); 
            for (i = 0; i < 3; i++) 
            { 
                printf("%d, ", *(ptr  + i)); 
            } 
        }
        
       // Print the elements of the array 
    printf("\nThe elements of the array are: "); 
    for (i = 0; i < 5; i++) 
    { 
      printf("%d, ", *(ptr  + i)); 
     }     
             
        
    return 0; 
}

Memory successfully allocated using malloc.
The elements of the array are: 1
The elements of the array are: 2
The elements of the array are: 1, 2,
Enter the 3 more the elements of the array are
The elements of the array are: 3
The elements of the array are: 4
The elements of the array are: 5


The elements of the array are: 3, 4, 5,
The elements of the array are: 3, 4, 5, 0, 0,

Why I don't get output 1, 2, 3, 4, 5?

Edit : int* ptr = (int*)malloc(5 * sizeof(int));