Thread: I don't know why my code is wrong...

Question:
Example 1:
Input: num = 14
Output: 6
Explanation:
Step 1) 14 is even; divide by 2 and obtain 7.
Step 2) 7 is odd; subtract 1 and obtain 6.
Step 3) 6 is even; divide by 2 and obtain 3.
Step 4) 3 is odd; subtract 1 and obtain 2.
Step 5) 2 is even; divide by 2 and obtain 1.
Step 6) 1 is odd; subtract 1 and obtain 0.
Example 2:
Input: num = 8
Output: 4
Explanation:
Step 1) 8 is even; divide by 2 and obtain 4.
Step 2) 4 is even; divide by 2 and obtain 2.
Step 3) 2 is even; divide by 2 and obtain 1.
Step 4) 1 is odd; subtract 1 and obtain 0.

Code:

Code:

#include<stdio.h>


int main(){


int numberOfSteps(int num){


    int steps=0;
    printf("Please enter the number:");
    scanf("%d",&num);
    while(num!=0){
        num=(num%2==0)?num/2:num-1;
        ++steps;
        
    }return steps;}}

Originally Posted by Salem

> num=(num%2==0)?num/2:num-1;
Try writing it out in long form.

This looks like you found this on google.

Oh, and C doesn't support nested functions.

Code:

#include<stdio.h>


int main(){


int num;




	int steps=0;
	printf("Please enter the number:");
	scanf("%d",&num);
	while(num!=0){
		num=(num%2==0)?num/2:num-1;
		steps ++;}
	
	return steps;
	}