Thread: How can I print a linked list that contains the path directory (environment variable)

Originally Posted by Salem

> I know the function listhpath returns a Node
You could have fooled me.

Here.
pathDirs = listpath(&pathCopy);
Is this better?

OMG! YOU ARE THE BEST THANK YOU!

To whom it may concern:

I just changed a little bit the main.c code, here's the final version of it:

Code:

int main()
{
  Node *head = NULL;
  Node *pathDirs = head;
  char *pathCopy = NULL;
  pathDirs = listpath(&pathCopy);
  while (pathDirs != NULL)
  {
    printf("\n %s\n", pathDirs->str);
    pathDirs = pathDirs->next;
  }
  return (0);
}

Then I typed the following compiling command:

Code:

gcc -Wall -Werror -Wextra -pedantic -std=gnu99 *.c -o printf_path

And here's the final output after executing the printf_path program :

Code:

root@691c473c3479:/printf_path# ./printf_path


 /bin


 /sbin


 /usr/bin


 /usr/sbin


 /usr/local/bin


 /usr/local/sbin

Once more, thanks for the assistance. This thread can be closed now.