Thread: Programs launched from C don't stay open after launcher closes

  1. #1
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    Programs launched from C don't stay open after launcher closes

    I'd like to be able to launch a program from this C program and have that launched program stay open after this C program closes.

    I've tried various solutions, and none seem to do the above. Here is some code that at least shows what's going on, and I know it doesn't work, but I wanted to at least put some effort code in here that might help.

    Code:
    #include <unistd.h>
    #include <sys/types.h>
    #include <sys/wait.h>
    #include <stdio.h>
    #include <stdlib.h>
    
    int main () {
    
        pid_t pid = -1;
    
        printf("\nParent is forking a child.");
    
        pid = fork();
    
        if(pid < 0){
    
            perror("fork");
            exit(1);
    
        }else if(pid == 0){
    
            printf("Starting child process...\n");
            printf("If I were to press ctrl-c here, both programs would close, but I want the launched program to stay open.\n");
    
            execlp("/usr/bin/xterm", "xterm", "-e", "top", NULL);
    
            // Code will never reach this point
    
        }else{
    
            printf("Parent is waiting for child id %d to complete...\n", pid);
    
            // Wait for procress to complete
            wait(NULL);
    
            printf("The child process is complete and has terminated!\nBut this program had to stay open the entire time.");
        }
    
        printf("Parent is now exiting...\n");
    
        return 0;
    }

  2. #2
    and the hat of int overfl Salem's Avatar
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    Just delete the call to wait(NULL);
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
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    Quote Originally Posted by Salem View Post
    Just delete the call to wait(NULL);
    Works perfect now. Thank you.

    SOLVED!

  4. #4
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    The child now remains open after the parents closes, but I noticed that in a loop, the child still dies if the parent is killed via ctrl-c.

    How can I keep the child alive regardless of how the parent is killed?

    Code:
    #include <stdlib.h>
    #include <string.h>
    #include <unistd.h>
    #include <sys/wait.h>
    #include <stdio.h>
    #include <signal.h>
    
    /* Compile and run with:
    
    gcc -Wall run.c -o run -lncursesw && run 
    
    */
    
    void handler(int signum) {
    
        write(STDOUT_FILENO, "\nExiting gracefully.", 20);
        printf("\n");
        exit(1);
    
    }
    
    void execute(char **arg) {
    
         pid_t  pid;
         int exec;
    
         if ((pid = fork()) < 0) {
    
              exit(1);
    
         } else if (pid == 0) {
    
              exec = execvp(*arg, arg);
    
              if (exec < 0)
                   exit(1);
    
         } else {
    
            //while (waitpid(-1, NULL, WNOHANG) != pid);
    
         }
    
    }
    
    #define MAX_LINE 256 
    
    int main(int argc, char* argv[], char*envp[]) {
    
       char text[MAX_LINE];
       char *args[MAX_LINE/2 + 1]; // Calculate max elements possible
    
       signal(SIGINT, handler);
       signal(SIGKILL, handler);
       signal(SIGTERM, handler);
    
       do {
    
          printf("\nShell: ");
          fgets(text, MAX_LINE, stdin);
    
          text[strlen(text) - 1] = '\0'; // strip return carriage at end of text
          args[0] = strtok(text, " ");
    
          for (int i = 0; args[i] != NULL; )
             args[++i] = strtok(NULL, "\"' " ); // consider quotations too
    
          execute(args);
    
       } while (strcmp(text, "exit") != 0);
    
       return 0;
    }

  5. #5
    and the hat of int overfl Salem's Avatar
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    You could do the double fork.
    Code:
    if ( fork() == 0 ) {
      if ( fork() == 0 ) {
        execvp(*arg, arg);
      } else {
        _exit(0);
      }
    }

    daemon(3) - Linux manual page
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  6. #6
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    Quote Originally Posted by Salem View Post
    You could do the double fork.
    Code:
    if ( fork() == 0 ) {
      if ( fork() == 0 ) {
        execvp(*arg, arg);
      } else {
        _exit(0);
      }
    }

    daemon(3) - Linux manual page
    Nice. I haven't thought of forking within a fork. I'll try it out tomorrow.

  7. #7
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    Notice that exec?() WILL return in case of error.

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