Thread: atoi & scanf

  1. #1
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    atoi & scanf

    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    
    int main(void)
    {
            char input[100];
            int z;
    
    
            printf("Insert string: ");
            scanf("%s", input);
    
    
            z = atoi(input);
    
    
            printf("%d", z);
    
    
            return 0;
    }
    Please, z is returning zero. Would love an explanation with a fix.

  2. #2
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    "...a computer is a stupid machine with the ability to do incredibly smart things, while computer programmers are smart people with the ability to do incredibly stupid things. They are,in short, a perfect match.." Bill Bryson

  3. #3
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    Quote Originally Posted by stahta01 View Post
    T

    This actually isn't what I want. I wanted to write a program to convert CHAR into ASCII code.

  4. #4
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    I suggest you post the input with the output you want because what you stated is not clear to me.
    To me char is already ASCII!

    Tim S.
    "...a computer is a stupid machine with the ability to do incredibly smart things, while computer programmers are smart people with the ability to do incredibly stupid things. They are,in short, a perfect match.." Bill Bryson

  5. #5
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    Perhaps you want to print the value of each character?

    Code:
    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    int main(void)
    {
        char input[100];
    
        printf("Insert string: ");
        scanf("%99s", input);
    
        for(size_t i = 0; i < strlen(input); ++i)
            printf("%c = 0x%X = %d\n", input[i], (int)input[i], (int)input[i]);
    
        return 0;
    }

  6. #6
    null pointer Structure's Avatar
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    Post

    convert CHAR into ASCII
    Code:
    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    int main( int argc, char *argv[] ) {
        
        char input[100];
    
        printf( "String: " ); scanf( "%s", input );
    
        for (int i=0; i<strlen(input); i++) {
    
            int z = (int)(input[i]);
    
            printf( "%i,", z );
    
        }
     
        printf( "\n" );   
        return 0;
    }
    C - Type Casting - Tutorialspoint
    Last edited by Structure; 06-14-2021 at 05:12 AM.
    "without goto we would be wtf'd"

  7. #7
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    Post

    atoi & scanf
    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    int main( int argc, char *argv[] ) {
        
      char number[128];
    
      printf( "Enter Number: "); 
      scanf( "%s", number);
      
      int z = atoi( number );
      printf( "%i \n", z );
    
      return 0;
    }
    "without goto we would be wtf'd"

  8. #8
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    Looks good, thanks to all those that helped! Great to be back on the forum!

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