Thread: static array list

I'm trying to make static list that can add element in list. I know that's know the good way to make list but it's just experiment

only 5 digits allow in list

Program supposed to give result like this

add digit 1 in array then show array = 1
add digit 2 in array then show array = 1 2
add digit 3 in array then show array = 1 2 3
add digit 4 in array then show array = 1 2 3 4
add digit 5 in array then show array = 1 2 3 4 5


When array exceed limit size, stop adding digit

Code:

#include<stdio.h>


int main ()
{
	int i;
	
	int array[5];
	
	return 0;
}

I need a function that add one digit in array and show the array digits

I'm stuck with function I don't understand what's logic need to add one digit

To add first digit => array[0] = 1
To add second digit => array[1] = 2
and so on until 5th digit which will be in array[4]

To print the array use a simple for loop.

Originally Posted by thmm

To add first digit => array[0] = 1
To add second digit => array[1] = 2
and so on until 5th digit which will be in array[4]

To print the array use a simple for loop.

I can do that but I am looking for a function

Code:

#include<stdio.h>

int main ()
{
	int i;
	
	int array[5] = {1};
	
	for ( i = 0; i <5; i++)
		printf(" %d", array[i]);
	    
		array[1] = 2;
	
    printf("\n");
	
	for ( i = 0; i <5; i++)
		printf(" %d", array[i]);
	
		array[2] = 3;
	
    printf("\n");
	
	for ( i = 0; i <5; i++)
		printf(" %d", array[i]);
	
	    array[3] = 4;
	
    printf("\n");
	
	for ( i = 0; i <5; i++)
		printf(" %d", array[i]);
	
	
       array[4] = 5;
	
    printf("\n");
	
	for ( i = 0; i <5; i++)
		printf(" %d", array[i]);
	
	return 0;
}

1 0 0 0 0
1 2 0 0 0
1 2 3 0 0
1 2 3 4 0
1 2 3 4 5

Originally Posted by john.c

Maybe:

How do you do if number is not in sequence ?

2
2 9
2 9 3
2 9 3 6
2 9 3 6 5