Thread: Simple linked list

Hi,

I have created list that only add two numbers

Code:

#include<stdio.h>
#include<stdlib.h> 
    
struct Node  
{ 
  int X;               // Structure Member 
  struct Node *Next;   // Structure Member 
}; 


int main() 
{ 
  struct Node* Head = NULL; // Declear pointer to structure 
  struct Node* Tail = NULL; // Declear pointer to structure 
   
  Head  = malloc(sizeof(struct Node));  // Allocate memory for Head
  Tail = malloc(sizeof(struct Node));  // Allocate memory for Tail
  
  Head -> X = 1; //assign value in first node 
  Head -> Next = Tail; // assign address of next Node    
     
  Tail -> X = 2; //assign data to second node 
  Tail -> Next = NULL;   
  
  printf(" %d \n", Head -> X); // Print value of First Node 
  printf(" %d \n", Tail -> X); //// Print value of Second Node 
     
   
  return 0; 
}

I want to print address of followings
Head
Tail
Head -> X
TAIL -> X
Head -> Next
Tail -> Next

I don't have any idea how to do it.

Thank you
Rahul

List traversal.

Code:

struct Node* temp = Head;
while ( temp ) {
  // do something with the current node
  printf("This=%p Next=%p Data=%d\n", 
    (void*)temp, (void*)temp->Next, temp->X );

  // advance to the next node.
  temp = temp->Next;
}