Thread: Changing characters to ***

and i'v made changes to the code, I'v removed all the junk and the 'username' part....and added coments!!!!!!!

I was wondering if you could please tell me the compiler that this code will work in because it does not want to seem to want to work in mine

Thanks

sp00k

Originally posted by Unregistered
to add the use of backspace, replace this with the inputcode() function:

Code:

//refer to the link from the previous post
...
void inputcode(char*&x)
{
 cout<<flush;
 for(i=0;i<8;i++)
 {
  x[i]=char(getch());
  cout<<"*"<<flush;
  if(x[i]==char(13) || x[i]=='\t' || x[i]=='\r' || x[i]==' '){break;}
  else if(x[i]=='\b'){cout<<"\b";i--;}
 }
 fillcode(++i); //fillcode(i+1);
}
...

- toaster

This is C++, and we're on a C board!

Now, you could all take note of Prelude's code which does what you want and is easily adapted to store the input for later use, or you could all waste more time talking about it. It's up to you

>hi you can get this one:
Exactly, why use 9 lines of code when you can write 83. That's much easier for the newbies to understand.
[/sarcasm]

Was Prelude's code that complex?

yes.......yes it was

First let me ask you, How was it so complex?
Second, do you still need help?

Originally posted by Commander
yes.......yes it was

OK, which part would you like help with?

Code:

/* Prelude's original code */
#include <stdio.h>	 
#include <conio.h>

int main(void)
{
	int ch;
		
	printf("Enter your password: ");
	while ((ch = getch()) != '\r') 
		putchar('*');
	printf("\nThank you\n");
	return 0;
}

Now, just to clarify, this code doesn't perform a password comparison. It mearly shows you how to best obtain the password from the user. To expand it to store the password, you'd need to store each ch in an array. You can also cater for backspace by simply removing the last character from the array when a backspace is read. Something like this:

Code:

#include <stdio.h>	 
#include <conio.h>
#include <ctype.h>

#define PASSLEN 10

int main(void)
{
	int ch, i;
	char password[PASSLEN+1];
			
	printf("Enter your password: ");
	
	i = 0;
	while ((ch = getch()) != '\r' && i < PASSLEN)
	{
		if (ch == '\b') 
		{	/* Handle backspace */
			if (i > 0) {i--; printf("\b \b");}
			password[i] = '\0';
		}
		else if (isalnum(ch))
			{	/* Only characters and numbers considered to be part of the password */
				password[i] = ch;
				putchar('*');
				i++;
			}
	}
	
	password[i] = '\0';
	printf("\nThank you, you entered: %s\n", password);
	return (0);
}

Alternatively, you could check each letter of the password as you get it from the user (instead of storing it in an array).

Also, doing this kind of thing:
>char master_password[] = "superdupervisor";
is not recommended. You only need to hex dump the exe and someone will find out the password. You should store it as encrypted text.