Thread: Confused in Pointer to Pointer address

Here's my code

Code:

#include <stdio.h>

void main(void)
{
    int num=10;
    int *numPtr1;
    int **numPtr2;

    numPtr1 = &num;
    numPtr2 = &numPtr1;
    printf("%d\n", num);
    printf("%d\n", *numPtr1);
    printf("%d\n", **numPtr2);
    printf("%p\n", &num);
    printf("%p\n", numPtr1);//here
    printf("%p", numPtr2);//and here
}

Why numPtr2's address is not the same with numPtr1?
printf("%p\n", numPtr1) and printf("%p", numPtr2) needs to display the same output right??

For example, let num's address 0x7fffaca780b4. Then when I run this code, the output is

**Output**
10
10
10
0x7fffaca780b4
0x7fffaca780b4
0x7fffaca780b8 <---????