Process terminated with status -1073741510 in Code::Blocks

[Konny]

Hello people,

I am pretty new to C and tried programming the quicksort algorithm.
But Code::Blocks keeps keeps terminating my process with the status above.
Also when printing my value, it says 6422272 instead of the I did put in.
Here is my Code:

#include <stdio.h>




void quicksort(int a[], int L, int R) //array, left end, right end
{
    int i, j, w, x, k;          // i is left index, r is right index, k is pivot
    i = L; j = R;
    k = (L + R) / 2;            // pivot set to middle
    x = a[k];                   // x gets value of k th element
    do
    {
        while(a[i] < x) i = i + 1;
        while(a[j] > x) j = j - 1;
        if(i <= j)
        {
            w = a[i];
            a[i] = a[j];        // swaps values of a[i] and a[j]
            a[j] = w;
            i = i + 1;
            j = j - 1;
        }
    }
    while(i <= j);                          // starts of on right and left side
    if(L < j) quicksort(a, L, j);
    if(R > i) quicksort(a, i, R);
}


int main()
{
    int length, value, i;
    printf("How long is your array?\n");
    scanf("%d", &length);       // I put 5 in
    printf("%d\n", &length);   // prints 6422272 
    int array[length];
    for(i = 0; i <= length; i++)
    {
        printf("Give value number %d\n", &i);
        scanf("%d", value);        
        array[i] = value;
    }
    quicksort(array, 0, length);
}

[Salem]

> printf("%d\n", &length); // prints 6422272
Because you don't use & when printing a value.

> for(i = 0; i <= length; i++)
Arrays run from 0 to length-1
So we usually say
for(i = 0; i < length; i++)

> printf("Give value number %d\n", &i);
> scanf("%d", value);
More goofiness over whether to use & or not.

Oh, and an explicit return 0; at the end won't go amiss either.