No he can't send you the code. You have to do it yourself.

Another solution is a count of repeated symbols. You just need a "last_flip" value initialized to an unused value (e.g., -1), and a count variable. count should start at 1 (since there is always "one in a row") and the count should be incremented anytime the current flip equals the last flip.

BTW, does anyone know how to calculate the average mathematically? It seems that the exact answer for the average of 3-in-a-row is 7, which is 2**3 - 1. In a simulation from 1-in-a-row to 10-in-a-row I get the following results, which are in line with the formula 2^n - 1.
Code:
min    max    average
  1      1       1.00
  2     22       3.00
  3     59       7.02
  4    188      15.02
  5    375      31.03
  6    820      62.93
  7   1537     127.06
  8   3549     254.79
  9   7086     510.40
 10  14034    1022.82