hello all
im wondering, when i use this code in windows over codeblocks:
long double ld=6;
scanf("%Lf",&ld);
printf("%f",ld); //// see, %f
the entered value returns correctly. when i use incorrect format, i must use %Lf in printf.
when i do not use the scanf function, i must use %Lf format.
any one knows what is happening?
For scanf to read a long double or for printf to print a long double, %Lf is correct.
The standard states for printf that "If any argument is not the correct type for the corresponding conversion specification, the behavior is undefined." That is, you must always use %Lf (or equivalents) to print long double with printf. If you use %f and it works as expected, then you're just lucky (or unlucky, as the case may be).
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
