Sorry guys for stupid question but..sitting 2 days but I cannot write a simple code. Code needs to tell me to rewrite Array number if its(-1 or over 50) thanks for help..Code:#include <stdio.h> int main() { int arr[10]; for(int i=0;i<10;i++) //Inserting 10 arrays { printf("Insert Array %d\n",i+1); scanf("%d",&arr[i]); } int n=10,a,min; //Finded smallest array min = arr[0]; for(a=1; a<n; a++) { if(arr[a]<min) { min = arr[a]; } } printf("Smallest number in array = %d\n", min); return 0; }
Last edited by dabraa; 11-15-2020 at 09:28 AM. Reason: found a mistake
Something like
Code:do { printf("Insert Array %d\n",i+1); scanf("%d",&arr[i]); if ( arr[i] < 0 || arr[i] > 50 ) { printf("Out of range\n"); } else { break; } } while ( 1 );
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
For some reasons it still doesnt want to work.. maybe you can copy-paste the whole code?
Maybe you can show what you tried.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Code:#include <stdio.h> int main() { int arr[10]; for(int i=0;i<10;i++) //Inserting 10 arrays { printf("Insert Array %d\n",i+1); scanf("%d",&arr[i]); } do ( arr[i] < 0 || arr[i] > 50 ) { printf("Out of range\n"); scanf("%d",&arr[i]); } else { break; } } while ( 1 ); int n=10,a,min; //Found smallest array min = arr[0]; for(a=1; a<n; a++) { if(arr[a]<min) { min = arr[a]; } } printf("Smallest number in array = %d\n", min); return 0; }
If anyone needs this code, thanks for help Salem!Code:#include <stdio.h> int main() { int x[10], min = 999999, i; for (i = 0; i < 10; i++) { int num; do { scanf("%d", &num); if (num < 0 || num > 49) printf("Wrong number\n"); } while (num < 0 || num > 49); x[i] = num; if (num < min) min = num; } printf("Minimum value: %d", min); return 0;
