Thread: Value of variable stuck as '1'. Newbie help.

--SOLVED--

Hey everyone, i'm new to coding (just started my degree in electrical engineering and coding in C is part of it).

I'm trying to create and test a simple menu where the user can select options 1-4 and I set up two printf tests (1 within the function and 1 in the main function) to display the chosen option. x however is always shown has having the value of '1' and will not update to the choice. What have I done wrong? Thanks in advance!

Code:

#include <stdio.h>


int pay_select(void);


void main(void)
{
    int choice = pay_select(); //run function where user selects option 1-4
    printf("Test 2 = %d", choice); //print selected option
    
}


int pay_select(void)
{
    int x;
    puts("opt 1 = £5"); //pay options
    puts("opt 2 = £10");
    puts("opt 3 = £15");
    puts("opt 4 = £20");
    
    x = scanf("%d", &x); //saves option selected
    printf("Test 1 = %d\n", x);
    return x;
}

> x = scanf("%d", &x); //saves option selected
The x (on the left) is the return result of scanf, which is the number of conversions that scanf performed.
Since you only have one format conversion in your format string, your choice of return result is 1 (success), 0 (no conversion) or EOF.

Try with just this to begin with.
scanf("%d", &x);