Thread: Address of array using scanf

  1. #1
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    Address of array using scanf

    can someone please explain why when we use scanf to get array input we don't have to put the & sign in front of the Var name of the array

    e.g
    char name[20];
    int id;
    printf("Enter stuid, name ");
    scanf("%d%s", &id, name);
    Why is & omitted here ? while for eg for the id i have to > &id
    why is this ??



  2. #2
    C++ Witch laserlight's Avatar
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    In most contexts, an array is converted to a pointer to its first element. The notable exceptions being when the array is an operand of the address-of operator & and the sizeof operator.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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    can you give an example of the exceptions you mention ? If possible?

  4. #4
    C++ Witch laserlight's Avatar
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    I already told them to you. What kind of example are you looking for?
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

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