can someone please explain why when we use scanf to get array input we don't have to put the & sign in front of the Var name of the array
e.g
char name[20];
int id;
printf("Enter stuid, name ");
scanf("%d%s", &id, name);
Why is & omitted here ? while for eg for the id i have to > &id
why is this ??
In most contexts, an array is converted to a pointer to its first element. The notable exceptions being when the array is an operand of the address-of operator & and the sizeof operator.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
can you give an example of the exceptions you mention ? If possible?
I already told them to you. What kind of example are you looking for?
Look up a C++ Reference and learn How To Ask Questions The Smart Way
