Thread: Unknown symbol.

I don't think that's a valid symbol in C. You might be looking at someone's attempt to tell you that whatever comes next should be run at the command line.

If you don't understand what I just wrote, show an example in which you saw this symbol being used.

The dollar sign doesn't appear as a token or part of a token in C. Probably because it might not be available in a non-American context. You do see it sometimes as an extension, but I'd agree that $> looks like an input prompt.

Originally Posted by Malcolm McLean

The dollar sign doesn't appear as a token or part of a token in C. Probably because it might not be available in a non-American context. You do see it sometimes as an extension, but I'd agree that $> looks like an input prompt.

No?

Code:

int main(void)
{
 int $ = 0;
}

Originally Posted by rstanley

Your code above won't even compile;

Please format your code with proper indentation. This is not a C Code Obfuscation contest.

Your if else statement is illegal.

Code:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <math.h>

long x(long y,long z)
{
   if(!z)
      return y;
   return x(z,y%z);
}

int main(void)
{
   long t,u,w=0,v=0;

   srand(time(0));

   for(;;)
   {
      t=rand();
      u=rand();

      if(x(t,u)-1);
      else
         ++v;

      system("clear") && system("cls");
      printf("\n\n\n %g\n\n\n",1/sqrt(((double)v)/((3<<1)*++w)));
   }
}

The code at the bottom is my signature. And both compile just fine (tested with gcc and clang on linux).

Originally Posted by Sir Galahad

No?

Code:

int main(void)
{
 int $ = 0;
}

That's an extension. Some compiler will accept dollar signs in identifiers, but some won't.
It's quite useful actually as it creates a namespace which cannot clash with conforming, portable code.

Originally Posted by Sir Galahad

No?

Code:

int main(void)
{
 int $ = 0;
}

According to C11, you're relying on "other implementation-defined characters", since $ is not in the list of non-digits and does not have the form of a universal character name. Anyway, it is irrelevant because TheGreekMan2000 asked about $> rather than just $

Originally Posted by Malcolm McLean

That's an extension. Some compiler will accept dollar signs in identifiers, but some won't.
It's quite useful actually as it creates a namespace which cannot clash with conforming, portable code.

Oh okay. Kind of annoying that a compiler would support an extension by default though. Code would be way more portable if that sort of thing would raise an error/warning instead.