How to access members to double pointer struct?

**vincentThorpe** · 05-10-2020

I'm creating a *Node inside a function (allocate and accessing its members) but when I try to access compiler jumps.

l've tried this (Node*)(*_node)->item = ""; but it says "suspicious pointer conversion".

Thanks in advance.

Code:

int main (int argc, char* argv[]) {
   Node *node;   
   // allocate new node
   initialize(&node);
   
   // print node
   if (!strlen(_node->item) )
      printf("[null, ");
   else
      printf("[%s, ", _node->item);

   if (!_node->next)
      printf("null]\n");
   else
      printf("*node]\n");

   return 0;
}
void initialize(Node **_node) {
   *_node = malloc( sizeof(Node));
   //how to l access to _node members???
   // _node->item = ""
   // _node->next = NULL;
}

**laserlight** · 05-10-2020

What you want to do is something like this:

Code:

void initialize(Node **_node) {
    *_node = malloc(sizeof(**_node));
    if (*_node) {
        (*_node)->item = "";
        (*_node)->next = NULL;
    }
}

But I suggest using another variable to make things simpler:

Code:

void initialize(Node **_node) {
    Node *node = malloc(sizeof(*node));
    if (node) {
        node->item = "";
        node->next = NULL;
    }
    *_node = node;
}

Be wary about setting node->item to be an empty string literal though: you can only do this safely if the item member is a const char* rather than a char*.

**vincentThorpe** · 05-11-2020

@laserlight Hey thank you for the answer that is what I was looking for. Good to have you in this community. Regards.

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