Hello
logical operation between x and y give z
there are three column R1, R2, R3Code:X Y Z 0 0 0 0 1 1 1 0 1 1 1 1
if R1 is 1, R2 should be 1
if R1 is 0 , R2 will be unchanged
How to write c program for above logic operation ?
OR Logic
AND LogicCode:0 | 0 = 0 0 | 1 = 1 1 | 0 = 1 1 | 1 = 1
Code:0 & 0 = 0 0 & 1 = 0 1 & 0 = 0 1 & 1 = 1
Last edited by Parth12; 02-26-2020 at 12:16 AM.
So what's the point of R3? And what does this have to do with x, y and z?Originally Posted by Parth12
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sorry I have updated previous question because R1, R2, R3 create confuse so Now I am just using X, Y and Z
assume X is status of flag, Y is status of bit and z show the change of Y when flag enable
X flag can be enable and disable and Y is bit
If X flag is disable, bit Y will not change but flag is set, bit Y should be high and Z show the change of y
You had the good idea of drawing a truth table, so let's do that:
This is the exact truth table you drew in post #1, and indeed it corresponds to what you described. You also drew the truth table for OR, and it corresponds to this exactly. So you have answered your own question: implement an OR.Code:X Y Z 0 0 0 0 1 1 1 0 1 1 1 1
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I am confuse with following logic operation, specially with shift operation
What will the final result of X
Code:X = 0 | 0 << 0X = 0 | 0 X = 0 X = 0 | 1 << 1 X = 0 | X = X = 1 | 0 << 1 X = 1 | X = X = 1 | 1 << 1 X = 0 X =
