In the following program I am trying to left shift a char variable.
Code:int main() { unsigned char c='0x0A'; printf("%c", (c << 4)); return 0; }
When I compile and run the program then it is giving garbage value. My requirement is 0xA0. Any suggestions on this.
Code:#include <stdio.h> int main() { unsigned char c = '\x0A'; // proper way to set to hex value printf("%X\n", c << 4); // print as hex integer return 0; }
A little inaccuracy saves tons of explanation. - H.H. Munro
0xA0 isn't ASCII or a valid UTF-8 char. In ISO-8859-1 (Latin1) or WINDOWS-1252 is a "non breaking space"...
The printed char depends on your encoding... Example... if you do:
You'll see a smiley in UTF-8 or "â~º" in WINDOWS-1252.Code:puts("\xe2\x98\xba");
Originally Posted by krkr
What is the difference between storing '0xAA' and '\xAA' in char.
My understanding about '0xAA' is, the ASCII value will be stored in memory. But my doubt is, why it prints only 41 during printf, which is ASCII value of 'A' not 'AA'.
Not sure what will be stored in memory when we use '\xAA'.
It seems to me that '0xAA' is a multi-character constant formed from the characters '0', 'x', 'A', and 'A', whereas '\xAA' is a character constant having a value of 0xAA.
Look up a C++ Reference and learn How To Ask Questions The Smart Way
Wow... I didn't notice the '0xAA' (between single quotes)...
If your requirement is 0xA0 after the shift then perhaps you should be writing unsigned char c = 0x0A; // (no single quotes etc necessary)
I got a doubt, what will happen if we assign a char variable without single quotes. So replaced c = '0x0A' with c=0x0A and printed using %c, I am getting junk value "▒" always. Tried replacing 0x0A with 0xAA, 0xBB etc. But same junk value "▒" is coming always. How it will store in memory if we assign without single quotes in a char variable.
If we print using %X then it is coming as 0xA0.
The problem is that you're using the %c format specifier to print a non-printable character in this context. Try: c=0x4B or c=0x7A
So you know that it is correct. You don't have to worry about the strange output you get when using %c instead. The value is not "junk"; it's the output that is "junk" because you're trying to print what is non-printable.
Last edited by laserlight; 01-20-2020 at 11:24 PM.
Look up a C++ Reference and learn How To Ask Questions The Smart Way
