memory allocation for two dimensional array

[Player777]

I have declared two dimensional array. I want to print array element and address of array element

I wrote program here

#include<stdio.h>

void main()
{
    int i, j;
    int array[2][4]={1, 2, 3, 4, 5, 6, 7, 8};
     for ( i=0; i<2; i++)
          for ( j=0; j<4; j++)
              printf("%d\n", array[i][j]);
              printf("%p\n", &array[i][j]);
}

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why program is not showing all the memory allocation ?

[Hodor]

Because you don't have opening and closing curly braces where you need them

Your code is this

#include<stdio.h>

void main()
{
    int i, j;
    int array[2][4]={1, 2, 3, 4, 5, 6, 7, 8};
     for ( i=0; i<2; i++)
          for ( j=0; j<4; j++)
              printf("%d\n", array[i][j]);
     printf("%p\n", &array[i][j]);
}

Unrelated, but main returns int, not void

[Player777]

Because you don't have opening and closing curly braces where you need them

Thanks

#include<stdio.h> 
int main()
{
    int i, j;
    int array[2][4]={1, 2, 3, 4, 5, 6, 7, 8};
     for ( i=0; i<2; i++) 
     for ( j=0; j<4; j++)
	 {
        printf("%d\n", array[i][j]);		
        printf("%p\n", &array[i][j]);
	 }
	 
	 return 0;
}

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