Thread: Scanf an integer - C

  1. #1
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    Scanf an integer - C

    Hey.

    Suppose I want to scanf an int - here it doesn't work if I just do:

    Code:
    int in;
    scanf("%i", &in);
    Why is it?
    What's the difference between that and:

    Code:
    float f;
    scanf("%f", &f);
    Thanks in advance.

  2. #2
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    I'm not sure what you're getting at. Both of those seems to "work".

    However, if you mean to only allow decimal input for the integer then it's better to use %d instead of %i since %i accepts inputs like 010 as octal (hence decimal 8, not 10), which is probably not what the user intended. Although %i is sometimes useful, especially for hex input in the for 0xab.
    A little inaccuracy saves tons of explanation. - H.H. Munro

  3. #3
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    @John - we are now discussing this issue at the other thread.
    Thank you!!!

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