Thread: warning: assignment from incompatible pointer type

I want to print name and age of person in program

Code:

#include <stdio.h>#include <stdlib.h>
#include <string.h>
 
 typedef struct Person
   {
   char     Name[20];
   int      Age;
   int     *next;
   }List;
 
int main()
   {
   List   *head = NULL;


   head = (List*)malloc(sizeof(List));
  
   head->Age = 20;
   strcpy(head->Name,"Abhi\n");
   head->next = NULL;


   while(!head)
      {
      printf(" %d ",head->Age);
      printf(" %s ",head->Name);


      head = head->next;
      };


   free(head);              


   return(0);
   }

warning: assignment from incompatible pointer type [-Wincompatible-pointer-types]
head = head->next;
^
What's wrong in the code ?

Originally Posted by laserlight

You declared next to be an int* instead of a struct Person*.

Also, you should typedef the struct to either Person or Node, not List.

Now code compile without warning but It doesn't print name and age

Code:

#include <stdio.h>#include <stdlib.h>
#include <string.h>
 
 typedef struct Person
   {
     char     Name[20];
     int      Age;
     struct  Person *next;
   }List;
   
int main()
   {
   List   *head = NULL;


   head = (List*)malloc(sizeof(List));
  
   head->Age = 20;
   strcpy(head->Name,"Abhi\n");
   head->next = NULL;


   while(!head)
      {
      printf(" %d ",head->Age);
      printf(" %s ",head->Name);


      head = head->next;
      };


   free(head);              


   return(0);
   }