Thread: Program doesn't print all letters entered by user

  1. #1
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    Program doesn't print all letters entered by user

    Program doesn't print all letters entered by user

    Code:
     #include<stdio.h>int main (void)
    {
    	int i;
    	char array[15];
    	int size;
    	
    	printf("promote user to enter size off array  :" );
    	scanf("%d",&size);
    	
    	for(i=0; i<size; i++)
    	{
    		printf("print array element : ", array[i]);
    		scanf("%c",&array[i]);
    	}
        
        return 0;
    
    
    }
    promote user to enter size off array :5
    print array element : print array element : a
    print array element : print array element : b
    print array element :

    Why does it only print two letters only ?

  2. #2
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    Perhaps you should print the variable after you have the user enter the value?

  3. #3
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    Nothing change happen it gives a same result

    Code:
    #include<stdio.h>
    
    int main (void)
    {
        int i;
        char array[15];
        int size;
         
        printf("promote user to enter size off array  :" );
        scanf("%d",&size);
         
        for(i=0; i<size; i++)
        {
            scanf("%c",&array[i]);
    		printf("print array element : ", array[i]);
            
        }
         
        return 0;
     
     
    }
    promote user to enter size off array :5
    print array element : a
    print array element : print array element : b
    print array element : print array element :

  4. #4
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    The problem is that 1. scanf() leaves the end of line character in the input buffer and 2. when using the "%c" format character leading whitespace is not skipped.

    To fix the problem you can either enter all the characters without pressing the enter key, "abcde", or force the "%c" format specifier to skip leading whitespace by using a space before the specifier " %c".

  5. #5
    and the hat of int overfl Salem's Avatar
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    > scanf("%c",&array[i]);
    If you want to read the next printable character (ignoring all white space), then add a leading space to your scanf format string.
    scanf(" %c",&array[i]);
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  6. #6
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    Quote Originally Posted by Salem View Post
    > scanf("%c",&array[i]);
    If you want to read the next printable character (ignoring all white space), then add a leading space to your scanf format string.
    scanf(" %c",&array[i]);
    Thanks salem I have another question where i am struggling




    I want to store multiple strings entered by user

    Code:
    #include<stdio.h>
    
    int main(void)
    
    
    {
    	unsigned int i;
    	
            char name[5][5]= {"bil","del","sen", "jan","gan"};
    	
    	for(i=0; i <5;i++)
    	{
    		printf("candidate name = %s \n",name[i]);
    	}
    	
    	
    	return 0;
    	
    }
    candidate name = bil
    candidate name = del
    candidate name = sen
    candidate name = jan
    candidate name = gan

    How to store multiple strings entered by user?

  7. #7
    and the hat of int overfl Salem's Avatar
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    Pretty much the same way

    char names[5][10];

    Then a loop of
    scanf( "%s",names[i] );
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

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