Program should be get 6 letter from user and then letter print them
this i have written
program outputCode:#include <stdio.h> int main() { char letter[5]; int i; printf("Enter the Name of letter \n"); for (i = 0; i < 5; i++) { scanf("%c \n",&letter); } for (i = 0; i < 5; i++) { printf("%c \n", letter[i]); } return 0; }
Enter the Name of letter
a
b
c
d
e
f
e
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%
why code doesn't print the entered letter ?
> why code doesn't print the entered letter ?
Because you aren't taking the input correctly. I don't know much about C and how to use printf but I'm pretty sure what you're doing is wrong.
I think this should work:
Code:int main (void) { char Letters[6]; // should be 6 and not 5 because your question says you wanna read 6 letters from user i.e. from index 0 through 5 int i; for (i = 0; i < 6; i++) { scanf("%c \n" , &letter[i]); // instead if &letter[i] you could also use (letter + i)Code:} for (i = 0; i < 6; i++) { printf("%c \n" , letter[i]); } return 0; }
Last edited by Zeus_; 10-15-2019 at 11:07 AM.
Hi,
you're right. I think it would be good to clear with a little function
the keyboard-buffer to prevent that the next call of 'scanf'
takes the signs who are in the keyboard-buffer after the last
call of 'scanf':
Code:#include <stdio.h> void clearKeyboardBuffer(void) { while (getc(stdin) != '\n') ; } int main(int argc, char **argv) { char letter[5]; int i; printf("Enter the Name of letter \n"); for (i = 0; i < 5; i++) { printf("Enter letter %d: ", i); scanf("%c", &letter[i]); clearKeyboardBuffer(); } for (i = 0; i < 5; i++) { printf("Nr:%d %c\n", i, letter[i]); } return 0; }
