Bellow I show some code that I got from a tutorial.

I am interested in understanding what are some changes that I can make to this code so that I will end up in the block:

Code:
    if (ptr == NULL) {
        printf("Memory not allocated.\n");
        exit(0);
The code:
Code:
#include <stdio.h>
#include <stdlib.h>

int main() {
    // This pointer will hold the 
    // base address of the block created 
    int* ptr;
    int n, i, sum = 0;

    // Get the number of elements for the array 
    n = 5;
    printf("Enter number of elements: %d\n", n);

    // Dynamically allocate memory using malloc() 
    ptr = (int*) malloc(n * sizeof (int));

    // Check if the memory has been successfully 
    // allocated by malloc or not 
    if (ptr == NULL) {
        printf("Memory not allocated.\n");
        exit(0);
    } else {

        // Memory has been successfully allocated 
        printf("Memory successfully allocated using malloc.\n");

        // Get the elements of the array 
        for (i = 0; i < n; ++i) {
            ptr[i] = i + 1;
        }

        // Print the elements of the array 
        printf("The elements of the array are: ");
        for (i = 0; i < n; ++i) {
            printf("%d, ", ptr[i]);
        }
    }
}
So I don't want to receive the message: "Memory successfully allocated using malloc", but "Memory not allocated"