Thread: Manually reading a character literal

So I've started with the easiest to deal with annoyance, escape characters, this is the function I got so far:

Code:

int rdEscChr( int_c_voidp_t getchr, void *source, int c, char32_t *c32 ) {
	uint_least64_t num = 0;
	char text[5] = {0};
	str_t str = {0};
	if ( c !== '\\' ) {
		c = -1;
		goto rdEscChr_done;
	}
	str.txt = text;
	str.cap = 5;
	switch ( (c = getchr(source)) ) {
	case '0':
		c = getchr(source);
		if ( !isdigit(c) )
			break;
		c = rdU64_base62( getchr, source, c, 8, 0, &num );
		goto rdEscChr_done;
	case 'b': num = '\b'; break;
	case 'f': num = '\f': break;
	case 'n': num = '\n'; break;
	case 'r': num = '\r'; break;
	case 't': num = '\t'; break;
	case 'u':
		text[0] = getchr(source);
		text[1] = getchr(source);
		text[2] = getchr(source);
		text[3] = getchr(source);
		str.len = 4;
		(void)rdU64_base62( (int_c_voidp_t)sgetc, &str, sgetc(&str), 16, 0, &num );
		break;
	case 'v': num = '\v'; break;
	case 'x':
		text[0] = getchr(source);
		text[1] = getchr(source);
		str.len = 3;
		(void)rdU64_base62( (int_c_voidp_t)sgetc, &str, sgetc(&str), 16, 0, &num );
		break;
	// Escape characters \ ' " and ^ do not need to be explicitly defined here
	default: num = c;
	}
	c = getchr(source);
	rdEscChr_done:
	if ( c32 ) *c32 = (char32_t)num;
	return c;
}

If you want the details of rdU64_base62, str_t and sgetc then refer back to a previous thread of mine: Manually reading an integer literal
I'll worry about making those C89 compatible later if I decide to put them in a library (which I am considering atm).

Anyways does anyone see any potential problems or missing stuff?

Edit: Within a minute or 2 of posting this I noticed a bunch of problems myself and fixed them, I've now replaced the above code with that.