Thread: Passing pointer to array of struct pointers

Hello everyone,

I've been learning C for a few months now and I'm stuck on an aspect of passing pointers.


Here's what I think is a pointer to an array pointer of struct pointers:

Code:

#include <stdio.h>
#include <stdlib.h>
#define ARR_SIZE 5


struct my_struct{
    int num_one;
    int num_two;
};


int main (void)
{
    struct my_struct* struct_arr[ARR_SIZE];
    for(int i = 0; i < ARR_SIZE; i++)
    {
        struct_arr[i] = malloc(sizeof(struct my_struct));
        struct_arr[i]->num_one = i;
        struct_arr[i]->num_two = i + 50;
    }


    struct my_struct *(*p)[] = &struct_arr;

    for(int i = 0; i < ARR_SIZE; i++)
    {
        printf("array member: %d\n", i);
        printf("num_one: %d - num_two: %d\n\n", (*p)[i]->num_one, (*p)[i]->num_two);
    }
    return 0;
}

I can access and modify the elements by using (*p)[i], as shown above. But what is the syntax to pass *(*p)[] to a function to modify?

Code:

void mod_arr (struct my_struct *(*ms))
{
    for(int i = 0; i < ARR_SIZE; i++)
    {
        (*ms)[i]->num_one = 50;
        (*ms)[i]->num_two = 30;
    }
}
//I'm trying to call the function like this:
mod_arr(*(*p));

I've tried what feels like every variation of syntax in the arguments and I cannot find the correct way to pass. Thanks in advance!

Thanks for your reply, I can see now that I've added an unnecessary layer. And that I can use mod_arr(&(*p));
Cheers!

I just saw your edit... I'm really over complicating my calls

Thanks again!