Thread: incompatable type for argument 1 of enter address

  1. #1
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    incompatable type for argument 1 of enter address

    i have this code:
    Code:
    #include <stdio.h>
    #include <stdlib.h>
    
    typedef struct
    {
        int door_number;
        char street;
        char town;
        char county;
        char postcode;
    }Address;
    
    void enter_address(Address *p_address)
    {
        p_address->door_number = 1;
        //etc etc
    }
    int main()
    {
        int i;
        Address book[20];
    
        for (i = 0; i < 20; i++)
        {
           enter_address(book[i]);
        }
        return 0;
    }
    i know the solution is to call enter address like this
    Code:
     enter_address(book + entrys)
    but what i don't understand is why since array[1] is the same as array + 1

    is this just another example of c stands for contrary
    Last edited by cooper1200; 05-18-2019 at 03:18 AM.

  2. #2
    and the hat of int overfl Salem's Avatar
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    Because [] dereferences.

    > but what i don't understand is why since array[1] is the same as array + 1
    Except it isn't.

    book is an array.

    In the context of calling a function, enter_address(book) is just the same as enter_address(&book[0])

    In short, enter_address(book+i) and enter_address(&book[i]) are the same thing, and what you want.

    enter_address(book[i]) is something completely different.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
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    Quote Originally Posted by Salem View Post
    In short, enter_address(book+i) and enter_address(&book[i]) are the same thing, and what you want.
    ok i think that is where i was getting confused
    coop

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