Thread: struggeling with an if statment clause

  1. #1
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    struggeling with an if statment clause

    ill try to explain the clauses for it to be true

    x can be 1 or -1 but has to be one of those 2
    y has to be 1 if king is false or y can be 1 or -1 if king is true
    Code:
      
        x=1 | x=-1 | y=1 | y=-1 | king true | king false | desired result
        ____|______|_____|______|___________|____________|_________________
          0 |  1   |  0  |  1   |    0      |    1       |   0
          0 |  1   |  1  |  0   |    0      |    1       |   1    
          1 |  0   |  0  |  1   |    0      |    1       |   0
          1 |  0   |  1  |  0   |    0      |    1       |   1
          0 |  1   |  0  |  1   |    1      |    0       |   1
          0 |  1   |  1  |  0   |    1      |    0       |   1    
          1 |  0   |  0  |  1   |    1      |    0       |   1
          1 |  0   |  1  |  0   |    1      |    0       |   1
    hopefully the truth table will come out ok
    coop

  2. #2
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    i have tried
    Code:
    if (((x == -1 || x == 1) && (y == 1 || y ==-1) && king == true) || ((x == -1 || x== 1) && y == 1))
    but it always was true regardless of y and the king
    coop

  3. #3
    and the hat of int overfl Salem's Avatar
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    I would focus on the two result=0 cases.

    This is true, regardless of the state of x/y
    if ( king == 1 ) result = 1;

    Also
    if ( !king && ( (x==-1 && y==-1) || (x == 1 && y== -1) ) ) result = false;
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  4. #4
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    This is not a truth map.... I'm assuming (x==-1) means truth and (y==-1) means truth, otherwise, false. You'll end up with this table:
    Code:
    x=-1 | y=-1 | king true | result
     (A) |  (B) |    (C)    |   (S)
    _____|______|___________|_________________
     0   |  0   |    0      |    1 = ~A~B~C
     0   |  0   |    1      |    1 = ~A~BC
     0   |  1   |    0      |    0
     0   |  1   |    1      |    1 = ~ABC
     1   |  0   |    0      |    1 = A~B~C
     1   |  0   |    1      |    1 = A~BC
     1   |  1   |    0      |    0
     1   |  1   |    1      |    1 = ABC
    Using a kmap (as I showed before), you can simplify this with:
    struggeling with an if statment clause-map-png
    Which will result in S=~B || C. Your condition should be:
    Code:
    if (y==1 || king ) ...

  5. #5
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    trouble is i havent done demorgans and kaunaugh for about 25 years and then it confused me how you decided which square was A and which was ~A for example however i take your point all i need is the statment
    if ((king == true || y == 1) && (x == -1 || x == 1)) as although x doesn't infulence the outcome i need to test that it is either 1 or -1

    coop
    Last edited by cooper1200; 05-07-2019 at 09:21 AM.

  6. #6
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    Quote Originally Posted by cooper1200 View Post
    trouble is i havent done demorgans and kaunaugh for about 25 years and then it confused me how you decided which square was A and which was ~A
    It is in the FIRST sentence on my text!
    Quote Originally Posted by cooper1200
    for example however i take your point all i need is the statment
    if ((king == true || y == 1) && (x == -1 || x == 1)) as although x doesn't infulence the outcome i need to test that it is either 1 or -1
    Then, again, your truth table is wrong... There are 5 vars, not 6, unless "king" can be different from true or false.
    With 5 vars you should have a truth table with 32 entries... with 6, 64...

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