Why does the output give a as the memory address’? I want it to show the current integer on the loop.Code:#include <stdio.h> #include <stdlib.h> int main() { int a; int howMany; int maxAmmt = 10; printf("How many lines do you want to loop? (Max 10)\n"); scanf("%d", &howMany); for(a = 1; a <= maxAmmt; a++){ printf("%d\n, a"); }
You misplaced a double quote, i.e., it should have been:
Code:printf("%d\n", a);
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
I won’t say what I want to say in case of children. But I get so frustrated at myself for not catching these little typos! I try so hard to go over and over the code, but it’s like selective dyslexia for me. Sorry to bug you on something small again.
Try compiling at a high warning level. Your compiler may give you a warning that would make your mistake more obvious to you.
Look up a C++ Reference and learn How To Ask Questions The Smart Way
Don't be too hard on yourself - You're always going to make mistakes; everyone does.
The difference is that as you get more experienced you'll be able to pick up on what is going wrong.
Looking at other peoples code on forums like this helps as well - You'll see that the same problems keep coming back up.
Like the classic...
Have a look at it and see if you can see and fix the problemCode:scanf("%d", apple); // doesn't work...
(No one give him the answer)
Fact - Beethoven wrote his first symphony in C
Ctylersills, in MY experience, it is impossible to write a code without syntatic errors... In my coding I write something, compile it and get a lot of errors and warnings...
Click_here tip if gold: Compile it with all available warnings enabled (-Wall -Wextra) and let the compiler check possible errors for you.
But, sometimes we do valid, but wrong things, anyway... In this case, use a debugger (GDB, por instance)...
[]s
Fred
