C Programming HELP!!

[ProgramSam88]

Can anybody explain to me why the second Array is getting a value from the first set??
My keylist.txt file is simply "2 14 74 8 36 4 11" but for some reason it keeps assigning the '2' value to the second array.

*********************************************

#include <stdio.h>

int main(){
    int keylist[6], guess_list[6], game = 1;
    char file_name[30];

    FILE * ifp;

    for(int i = 0; i<7; i++){
        keylist[i] = 0;
        guess_list[i] = 0;
    }


    ifp = fopen("keylist.txt", "r");

    for(int i=0; i<7; i++){
        fscanf(ifp, "%d", &keylist[i]);
    }

    for(int i=0; i<7; i++){
        printf("%d, %d\n", keylist[i], guess_list[i]);
    }

return 0;
}

*********************************************

[Salem]

> for(int i = 0; i<7; i++)
Because 7 is greater than 6.

for(int i = 0; i<6; i++)
is how you index an array of 6 elements.

Otherwise known as a fence-post error.

[ProgramSam88]

> for(int i = 0; i<7; i++)
Because 7 is greater than 6.

for(int i = 0; i<6; i++)
is how you index an array of 6 elements.

Otherwise known as a fence-post error.

But the array holds 7 numbers, 0,1,2,3,4,5,6..... it still is not working.

[Salem]

No, the arrays hold 6 values.

> But the array holds 7 numbers, 0,1,2,3,4,5,6..... it still is not working.
7, 8, 100, a gigabyte - it's all the same (a buffer overrun).

If you consider "works" as being the same as "doesn't crash" then you're in for some painful lessons.

[Click_here]

I think that you are getting confused with how to use arrays in the c language.

int grape[5];

This creates an array of 5 ints

To access each element you have

apple = grape[0]; // 1st element

apple = grape[1]; // 2nd element

apple = grape[2]; // 3rd element

apple = grape[3]; // 4th element

apple = grape[4]; // 5th element

If I were to try an access grape[5], this would be the sixth element...

Arrays in C - Cprogramming.com