4 times pointer

[roko1983A]

Hi Experts

for a homework im trying to fill and print a quadruple cube using a 4 times pointer

#include <stdio.h>
#include <stdlib.h>


#define DIM 4


void printCube(char**** cube, int dim) {
  int x, y, z;
  for(z = 0; z < dim; z++) {
    for(y = 0; y < dim; y++) {
      for(x = 0; x < dim; x++) {
        printf("%c ", *cube[z][y][x]);
      }
      printf("\n");
    }
    printf("------------------------------------\n");
  }
}


int main() {
  char*** cube = (char***)malloc(sizeof(char**) * DIM);
  int x, y, z;
  for(z = 0; z < DIM; z++) {
    cube[z] = (char**)malloc(sizeof(char**) * DIM);
    for(y = 0; y < DIM; y++) {
      cube[z][y] = (char*)malloc(sizeof(char*) * DIM);
      for(x = 0; x < DIM; x++) {
        cube[z][y][x] = ((x + y + z) % 26) + 'A';
      }
    }
  }


  printCube(&cube, DIM);


  for(z = 0; z < DIM; z++) {
    for(y = 0; y < DIM; y++) {
      for(x = 0; x < DIM; x++) {
        free(cube[z][y][x]);
      }
      free(cube[z][y]);
    }
    free(cube[z]);
  }
  free(cube);
  return 0;
}

I tried now for several hours to correct this code. I found out that the error should be at this statement printf("%c ", *cube[z][y][x]); because printing without the pointer works fine. But im unsure how i can should use the pointer to print the cube...

Really would appreciate your support

[Salem]

Like this.

printf("%c ", (*cube)[z][y][x]);

Oh, and remove all your malloc casts.

[john.c]

#include <stdio.h>
#include <stdlib.h>
 
void printCube(char*** cube, int dim) {
    for (int z = 0; z < dim; z++) {
        for (int y = 0; y < dim; y++) {
            for (int x = 0; x < dim; x++)
                printf("%c ", cube[z][y][x]);
            printf("\n");
        }
        printf("-------\n");
    }
}
 
int main() {
    int dim = 4;
    char*** cube = malloc(dim * sizeof *cube);
    *cube = malloc(dim * dim * sizeof **cube);
    for (int z = 1; z < dim; ++z)
        cube[z] = cube[z - 1] + 1;
    **cube = malloc(dim * dim * dim * sizeof ***cube);
    for (int z = 0; z < dim; ++z)
        for (int y = 1; y < dim; ++y)
            cube[z][y] = cube[z][y - 1] + 1;
 
    for (int z = 0; z < dim; z++)
        for (int y = 0; y < dim; y++)
            for (int x = 0; x < dim; x++)
                cube[z][y][x] = ((x + y + z) % 26) + 'A';
 
    printCube(cube, dim);
 
    free(**cube);
    free(*cube);
    free(cube);
 
    return 0;
}