Pointers & Arrays

**Nikosant03** · 02-09-2019

Dear all I am new in C programming and at the moment I am studying array and pointers.

This piece of code is from an exercises I was looking and declares a function findMax as a pointer passing two arguments int arr[] and int n. The number of data values n is used to specify the size of the array.. What I dont undertand is the int arr[n] point.

Can someone explain me how this piece of code is working?

Thanks in advance

int *findMax(int arr[],int n);
int main(){
int n,i,*p;
printf("Enter number of data values");
scanf("%d",&n);
int arr[n];

**laserlight** · 02-09-2019

That declares arr to be a variable length array of n int elements. The variable length array feature was introduced in the 1999 edition of the C standard, but later became optional, so it is possible that your compiler might not support it.

**Nikosant03** · 02-09-2019

Originally Posted by laserlight

so it is possible that your compiler might not support it.

This is the reason I was asking for explanation because while compiling it returns an error of "error C2133: 'arr': unknown size"

In order to create a variable length array in C I should use the malloc function?

**laserlight** · 02-09-2019

Yes, that would be an option.

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