Thread: A problem in remainder

  1. #1
    Registered User
    Join Date
    Jan 2019
    Posts
    1

    A problem in remainder

    Hello, I am a student and a beginner learning c.
    I need help where I did wrong in the following code

    Code:
    #include <stdio.h>
    int main(void){	int s,j,i,r;
            printf("Enter an integer: ");	scanf("%d",&i);
    	s=i-1;	int n[s];
    	for(j=1,s=0;s<i-1;j++,s++)	{	  n[s]=j+1;	  r=n[s]%2;      printf("n[%d]remainder2=%d \n",n[s]%2,r);    }}
    I am getting the output:

    Code:
    Enter an integer: 9
    n[0]remainder2=0
    n[1]remainder2=1
    n[0]remainder2=0
    n[1]remainder2=1
    n[0]remainder2=0
    n[1]remainder2=1
    n[0]remainder2=0
    n[1]remainder2=1
    In the loop after executing two times, the same process repeats.
    Thanks for the help
    Last edited by Salem; 01-21-2019 at 08:55 PM. Reason: Use [code][/code] tags for C/C++

  2. #2
    Registered User
    Join Date
    Jan 2019
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    It's difficult to tell what you're trying to do here. Please use descriptive variable names (instead of s,j,i,r) and format your code properly.

  3. #3
    Guest
    Guest
    Hello newstein, in the future post you code between [code][/code] tags and see that it maintains indentation from your editor, i.e.
    Code:
    #include <stdio.h>
    
    int main(void)
    {
        int s, j, i, r;
        printf("Enter an integer: ");
        scanf("%d",&i);
        s = i - 1;
        int n[s];
        for (j = 1, s = 0; s < i - 1; j++, s++) {
            n[s] = j + 1;
            r = n[s] % 2;
            printf("n[%d]remainder2=%d \n", n[s]%2, r);
        }
    }

  4. #4
    Registered User
    Join Date
    Dec 2017
    Posts
    1,626
    It's also important to describe what the code is supposed to do and what output you expect.
    A little inaccuracy saves tons of explanation. - H.H. Munro

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