Histogram

[Audy Naufal]

Here is the question :



This is my code that I have made :

#include <stdio.h>
#include <string.h>


void count(char str[]);


int main()
{
    char text[80];
    printf("Enter a string : ");
    gets(text);
    count(text);
    return 0;
}


void count(char str[])
{
    int i, j, count;
    for (i = 0; str[i] != '\0'; i++)
    {
        count = 0;
        for (j = 0; str[j] != '\0'; j++)
        {
            if (str[j] == str[i])
            {
                count++;
            }
        }
        printf("%c : %d\n", str[i], count);
    }
}

My question is, how can i print the character in a type of an array based on their alphabetical arrangement ?

[Salem]

First, posting "Hi, i wonder that you can help me to solve my problem. please !" as your title for every post isn't helpful.

> char text[80];
> printf("Enter a string : ");
> gets(text);
1. Your input lines are up to 1000 characters.
2. There is no mention of prompting for input.
3. Your first line of input is the number of test cases. These programs are tested automatically, so you need to follow the input file spec closely.
4. NEVER EVER use gets(). It is totally unsafe. It's even been removed from the latest C standard. Use fgets() instead.


I suppose you can start with understanding how this works.

int counters[26] = { 0 };
char c = 'B';  // for example
counters[c - 'A']++;