Thread: Not doing free()

Hi ;
In abbreviation, the concept is deleting third entry of linked lists;
if I have a linked lists (it's one direction) and lets say I have jumped from the second entry of linked lists to the fourth entry ; meaning with this I have updated the pointer of Node * next of second entry to point on the fourth entry, what happen to third entry, I'm not having access to it at all, this means implicitly I have deleted it, my question will PC free it by itself? if not doing free to it as, will the data of entry three be saved forever in the memory?! it's not logically.


thanks !