Hi,
there's something a lily confused me of how it's working when the PC getting an operation from an instruction, for instance and to be easy when I say to the compiler int y=z+x (assuming that z and x already defined ); my question is, the processor gets that operation and analogy say, well now I have the "y=z+x", I will put "breakpoint/note" to get back to "z+x", because now I'm going to where the data of x, after wards going to the data of z (or going opposite-doesn't matter) ; and then I will back to where I have put the breakpoint, i.e to y=z+x , now I can Add ! ; that's actually what I'm thinking that PC done, but is it really what he's doing? or am I missing something more significant?!
thanks for your cooperative
