Thread: Need help.

Do you know how to do an average in general? As your printf is showing you, you can treat str1[i] as a numerical value, so you don't have to do any conversions to get the ASCII values.

You mean generally in math? then yes. Sum divided by number of elements.
But idk how to make a sum of the characters that are str1[i]==str2[i].
Thanks for the reply

You're already doing the check whether str[1]==str[2]; inside that if statement you can add to a running total, and also add 1 to the count of matched characters. (You'll have to initialize total and count to zero before you start, of course.)

Shortly after you told me that I managed to do it, I looked online how someone else did the average and saw he did something similar to what I tried but the only thing was I wrote float where I shouldn´t so it didn´t work.
But anyways here it is

Code:

#include <stdio.h>
#include <string.h>

float my_compare(char str1[], char str2[], int indexStart, int indexEnd);

int main() 
{
    
    char str1[50];
    char str2[50];
    int a;
    int b;    
     
    
    printf("\nEnter the first string:");    
    fgets(str1,50,stdin);

    printf("\nEnter the second string:");
    fgets(str2,50,stdin);
do{
    printf("\n(Start index can’t be bigger then the end index.)\nPlease enter the start index: ");
    scanf("%d",&a);

    printf("Please enter the end index: ");
    scanf("%d",&b);
        
}    while (b<a);
    
     int c = my_compare(str1, str2, a, b);
}

float my_compare(char str1[], char str2[], int indexStart, int indexEnd)
{ 

    float sum = 0;
    float e = 0;
    float avrage = 0;

    for(int i=indexStart; i<indexEnd; ++i) //this is the substring for both str1 and str2
    {
        if(str1[i]==str2[i]) //only the same characters
        {    
        printf("\n %4c --> %4d\n ", str1[i], str1[i]);
        sum += str1[i];
        ++e; 
        }
    
    }
    avrage = sum/e;
    printf("The average ASCII sum of the compared strings is: %f\n",avrage);
}

Thank you for helping me