Why does this code fail after a full stop

[Valour549]

This is a program which replaces a certain word in a string, which I found here.

But when I'm playing around with it, I found that it fails to replace anything which is followed by a full stop. So any words that are meant to be replaced fails to be replaced if said word is at the end of a sentence. I've looked through the code and can't understand why?

#include <stdio.h>
#include <string.h>
#include<conio.h>
void main()
{
  char text[100],word[10],rpwrd[10],str[10][10];
  int i=0,j=0,k=0,w,p;
  clrscr();

      printf("PLEASE WRITE ANY TEXT.\n");
      printf("GIVE ONLY ONE SPACE AFTER EVERY WORD\n");
      printf("WHEN COMPLETE PRESS  Ctrl-Z  \n");
      gets(text);
      printf("\nENTER WHICH WORD IS TO BE REPLACED\n");
      scanf("%s",word);
      printf("\nENTER BY WHICH WORD THE %s IS TO BE REPLACED\n",word);
      scanf("%s",rpwrd);
      p=strlen(text);

      for (k=0; k<p; k++)
{

  if (text[k]!=' ')
    {
      str[i][j] = text[k];
      j++;
    }
  else
    {
      str[i][j]='\0';
      j=0; i++;
    }
}
str[i][j]='\0';
w=i;
       for (i=0; i<=w; i++)
{
   if(strcmp(str[i],word)==0)
      strcpy(str[i],rpwrd);

   printf("%s ",str[i]);
       }
   getch();
}

[Valour549]

Oh nevermind I figured it out xD

[Salem]

Did you also figure out

That gets() is bad.
FAQ > Why gets() is bad / Buffer Overflows - Cprogramming.com

That conio.h is obsolete.

That void main is wrong.
FAQ > main() / void main() / int main() / int main(void) / int main(int argc, char *argv[]) - Cprogramming.com

> This is a program which replaces a certain word in a string, which I found here.
Having read half a dozen, they're all awful examples.