Thread: HELP in homework

Originally Posted by Salem

So what are you stuck on?

Can you read a char and tell whether it's P, C or S ?

If you know you've chosen 'C' say, can you then go onto read parameters L,a,b ?

In short, you need to put forth some actual effort.
Colouring in your prose and dumping your assignment doesn't count.

Make an honest attempt, post your code where you get stuck, and ask a specific question.
Eg
"I can read all the parameters for C type capacitor, but why does it always prints zero?".
That is a specific question based on some coding effort.

this homework is much higher than my level
i dont use to make an main menu and make it work in a such program this why i ask for help to see if i can read it and understand it or no

i just finished my exams so i can deal with that by my own but i notice that there are a new things in this homework i dont remember that i took them
this why i ask for help (i cant even start ) because i think this will take days from me to understand what i can do with this task and organize it
but if you dont want to help me or you think why i am doing it because the dead line is come up its ok its not even "urgent" i am sure i can come up with the solution alone
but i need days and i have exams too
and yes this is my course ics 103 in kfupm

The program doesn't even have to be that fancy, you can use simple techniques and get it done, just start and ask a more concrete question.

You've done your exams, and even if you passed them with a mediocre grade, you shouldn't need total hand holding.

Code:

#include<stdio.h>
#include<math.h>
#define PI 3.14159
#define Eo 8.85e-6
int main ()

{
	int choice,type ;
	double C,d,l,a,b,area,air=1.000594*Eo,Teflon =2.1*Eo,Ceramic=5.6*Eo,Glass=7.5*Eo,Silicon=11.68*Eo,E,E2;
	printf ("---ccc-----\n");
	printf ("1.[p] Parallel Plates\n" );
	printf ("2.[c] Cylindrical\n");
	printf ("3.[s] sphereical\n" );
	printf("choice one plese:" );
	scanf("%d",&choice);
	
	switch (choice){
  case 1 :
   printf ("\nparallel plates was chosen!");
   printf ("\nEnter the area: ");
   scanf ("%lf",&area);
   printf ("\nEnter the distance between plates:");
   scanf ("%lf",&d);
   printf ("---type---\n");
   printf ("10.Air\n");
   printf("20.Teflon\n");
   printf("30.Ceramic\n");
   printf("40.Glass\n");
   printf("50.Silicon\n");
   printf("choice one plese: " );
   scanf("%d",&type);
   switch (type)
   case 10 :
    
    printf ("\nTYPE AIR WAS CHOSEN ! ");
       
       C= air*(area/d);
       printf ("\nthe result is %.2le micro farad",C);
	
          break ;
   case 20:
    
    E=Teflon*Eo;
    C= Teflon*(area/d);
    printf("Type TEFLON was chosen!");
    printf("\n the result is %.2le micro farad",C);
       break;
   case 30:
   
    C= Ceramic*(area/d);
     printf ("TYPE CERAMIC WAS CHOSEN !");
    printf ("\nthe result is %.2le micro farad",C);
    break;
    
   case 40 : 
    
    C= Glass*(area/d);
     printf ("TYPE GLASS WAS CHOSEN !");
    printf ("\nthe result is %.2le micro farad",C);
    
    break;
   case 50 : 
    
    printf ("\nTYPE SILICON WAS CHOSEN !");
    C= Silicon*(area/d);
    printf ("\nthe result is %.2le micro farad",C);
    return 0;
   }
   switch (choice)	
   {    
   case 2 : 
    printf ("Enter the length : ");
    scanf("%lf",&l);
    printf ("Enter radius a and b (a<b) ");
    scanf (" %lf %lf",&a,&b);
     printf ("---type---\n");
            printf ("10.Air\n");
           printf("20.Teflon\n");
           printf("30.Ceramic\n");
           printf("40.Glass\n");
           printf("50.Silicon\n");
           printf("choice one plese: " );
           scanf("%d",&type);
      switch (type)
   case 10 :
    
    printf ("\nTYPE AIR WAS CHOSEN ! ");
       C=(2.0*PI*air*l)/log(b/a);
       printf ("\nthe result is %.2e micro farad",C);
          break ;
          
   case 20 :
    
    C=(2.0*PI*Teflon*l)/log(b/a);
    printf("Type TEFLON was chosen!");
    printf("\n the result is %.2e micro farad",C);
       break;
       
   case 30 :
   
    C=(2.0*PI*Ceramic*l)/log(b/a);
     printf ("TYPE CERAMIC WAS CHOSEN !");
    printf ("\nthe result is %.2e micro farad",C);
    break;
    
   case 40 : 
   
    C=(2.0*PI*Glass*l)/log(b/a);
     printf ("TYPE GLASS WAS CHOSEN !");
    printf ("\nthe result is %.2e micro farad",C);
    break;
    
   case 50 : 
    
    printf ("\nTYPE SILICON WAS CHOSEN !");
    C=(2.0*PI*Silicon*l)/log(b/a);
    printf ("\nthe result is %.2e micro farad",C);
    
   return 0;
       
	}
	switch (choice)
	{
  case 3 : 
   printf("enter the inner and the outer (a<b) ");
   scanf ("%lf %lf",&a,&b);
    printf ("---type---\n");
            printf ("10.Air\n");
           printf("20.Teflon\n");
           printf("30.Ceramic\n");
           printf("40.Glass\n");
           printf("50.Silicon\n");
           printf("choice one plese: " );
           scanf("%d",&type);
      switch (type)
   case 10 :
    
    printf ("\nTYPE AIR WAS CHOSEN ! ");
       C=(4*PI*air*a*b)/b-a;
       printf ("\nthe result is %.2e micro farad",C);
          break ;
          
   case 20 :
    
    C=(4*PI*Teflon*a*b)/b-a;
    printf("Type TEFLON was chosen!");
    printf("\n the result is %.2e micro farad",C);
       break;
       
   case 30 :
   
    C=(4*PI*Ceramic*a*b)/b-a;
     printf ("TYPE CERAMIC WAS CHOSEN !");
    printf ("\nthe result is %.2e micro farad",C);
    break;
    
   case 40 : 
   
    C=(4*PI*Glass*a*b)/b-a;
     printf ("TYPE GLASS WAS CHOSEN !");
    printf ("\nthe result is %.2e micro farad",C);
    break;
    
   case 50 : 
    
    printf ("\nTYPE SILICON WAS CHOSEN !");
    C=(4*PI*Silicon*a*b)/b-a;
    printf ("\nthe result is %.2e micro farad",C);
    
                return 0;  }	
}