Thread: about dynamic memory arrays

I am trying to switch values stored inside arrays placed in heap. Program works like that.

Code:

 
void switchValue(int *a, int*b){
    
    int temp[]={1,2,3,4};
    for(int i=0; i<4; i++){
        temp[i]=a[i];
        a[i]=b[i];
        b[i]=temp[i];
    }
}
int main()
{
    int *A=(int*)calloc(4,sizeof(int));
    int *B=(int*)calloc(4,sizeof(int));
    
    A[0]=1, A[1]=2, A[2]=3, A[3]=4;
    B[0]=9, B[1]=8, B[2]=7, B[3]=6;
    
   switchValue(A,B);
    
    for(int i=0;i<4;i++){
        printf("%d ",A[i]);
        }


    printf("\n");
    
    for(int i=0;i<4;i++){
        printf("%d ",B[i]);
        }}

Compiler doesn't let me install my values like

Code:

A[]={1,2,3,4}

, no surprises. But what if I have 100 or 1000 values, I have to install my values like

Code:

A[0]=1, A[1]=2..

How can I store my values in heap easier?

Another question is when I create an array like int temp[4]; program dont stop working. I have to define values inside it(can see it in 3rd row of the code). I don't understand the problem.
Any help would be appreciated.
Thank you

How can I store my values in heap easier?

If your arrays are a "fixed" size then you could avoid using malloc/calloc and just use a static qualified array instead.

Code:

    static int A[] = {1, 2, 3, 4};

Another question is when I create an array like int temp[4]; program dont stop working.

Why is temp an array instead of just a single instance?

Thank you very much for both answers. And yes, I should definitely use single and static int for this code.